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# check cases converting float to int, relying only on single precision float
print(int(14187745.))
print(int(2.**100))
print("%d" % 14187745.)
print("%d" % 2.**100)
testpass = True
for i in range(0,128):
bitcnt = len(bin(int(2.**i))) - 3;
if i != bitcnt:
print('fail: 2**%u was %u bits long' % (i, bitcnt));
testpass = False
print("power of 2 test: %s" % (testpass and 'passed' or 'failed'))
# TODO why does 10**12 fail this test for single precision float?
testpass = True
for i in range(0,12):
digcnt = len(str(int(10.**i))) - 1;
if i != digcnt:
print('fail: 10**%u was %u digits long' % (i, digcnt));
testpass = False
print("power of 10 test: %s" % (testpass and 'passed' or 'failed'))
# test inf conversion
try:
int(float('inf'))
except OverflowError:
print("OverflowError")
# test nan conversion
try:
int(float('nan'))
except ValueError:
print("ValueError")
# test numbers < 1 (this used to fail; see issue #1044)
import struct
struct.pack('I', int(1/2))
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